20x^2=2-3x

Solution for 20x^2=2-3x equation:

20x^2=2-3x

We move all terms to the left:

20x^2-(2-3x)=0

We add all the numbers together, and all the variables

20x^2-(-3x+2)=0

We get rid of parentheses

20x^2+3x-2=0

a = 20; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·20·(-2)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-13}{2*20}=\frac{-16}{40}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+13}{2*20}=\frac{10}{40}
=1/4
$